Product of two natural numbers is 17.What is the sum of reciprocal of their squares?
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Answered by
3
290/289is the answer of the question
sidharthgupta:
firstly mark as breanlist answer
Answered by
2
If the numbers are a, b, then ab = 17,
as 17 is a prime number, so a = 1, b = 17.
1
a2
+
1
b2
=
1
12
+
1
172
=
290
289
as 17 is a prime number, so a = 1, b = 17.
1
a2
+
1
b2
=
1
12
+
1
172
=
290
289
can you explain once again please
If the numbers are a, b, then ab = 17,
as 17 is a prime number, so a = 1, b = 17.
1/a^2+1/b^2=1/1^2+1/17^2
=290/289
as 17 is a prime number, so a = 1, b = 17.
1/a^2+1/b^2=1/1^2+1/17^2
=290/289
If this helps you please mark as brainliest
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