Question

product of two number is 257. if their HCF is 2 find their LCM​

Answer 1

Step-by-step explanation:

Product=133848

Product=133848HCF=26

Product=133848HCF=26∴ the numbers are of the form

Product=133848HCF=26∴ the numbers are of the form26a, 26b

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.LCM of (26a,16b)=26ab

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.LCM of (26a,16b)=26abHCF × LCM = product of numbers.

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.LCM of (26a,16b)=26abHCF × LCM = product of numbers.26×26ab=133848

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.LCM of (26a,16b)=26abHCF × LCM = product of numbers.26×26ab=133848ab=676133848=198

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.LCM of (26a,16b)=26abHCF × LCM = product of numbers.26×26ab=133848ab=676133848=198∴ab=198

Product=133848HCF=26∴ the numbers are of the form26a, 26bWhen a and b are coprime.LCM of (26a,16b)=26abHCF × LCM = product of numbers.26×26ab=133848ab=676133848=198∴ab=198LCM=26ab=26×198=5148