Question

product of two numbers is 8192. if one number is twice the other. find the old num?

Answer 1

Hey there!

Let one no. Be X and the other be 2X

Then according to the question demand :

2x*x = 8192
2x^2= 8192
x^2= 8192/2
x^2= 4096
x=√4096
x=64

The other no =2x= 2*64= 128

Hence the nos.are 128 and 64..


# hope it helps!

Answer 2

Let one number = x
Other number = 2x
A.T.S
(2x) × (x) = 8192
2x^2 =8192
x^2 = 8192÷2
x^2 = 4096
x = under root 4096
x = 64

Therefore,
One no. = 65
Other no. = 2^x = 2 × 64 = 128


Hope it helps u ☺