Question

product of two rational number is -9/20 if one of them is -2/-15 then another rational number is​

Answer 1

${\large{\bold{Question::-}}}$

product of two rational number is -9/20 if one of them is -2/-15 then another rational number ?

${\large{\bold{given::-}}}$

• Product of two numbers = $\dfrac{-9}{20}$

• One of them = $\dfrac{-2}{-15}$

${\large{\bold{To\:Find::-}}}$

• Find another rational number .

${\large{\bold{Solution::-}}}$

Let another rational number be x.

A.T.Q.

             $⟼ \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{- 2}{ - 15} \times x = \dfrac{ - 9}{20}$

              $⟼  \: \: \: \: \: \: \: \: \: \: \: \: x = \dfrac{ - 9}{20} \times (\dfrac{ - 15}{ - 2} )$

               $⟼   \: \: \: \: \: \: \: \: \: \: \: \: x = \dfrac{ - 27}{ - 8}$

               $⟼    \: \: \: \: \: \: \: \: \: \: \: \: x = \dfrac{ 27}{ 8}$

Verification :-

                   $x = \dfrac{27}{8}$

Given equation :-

        $⟼   \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{- 2}{ - 15} \times x = \dfrac{ - 9}{20}$

          $⟼  \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{- 2}{ - 15} \times \dfrac{27}{8} = \dfrac{ - 9}{20}$

___________

By multiplying $➝   \: \: \: \: \: \: \: \: \: \: \: \: \dfrac{- 2}{ - 15} \times \dfrac{27}{8}$

We get :- $\dfrac{ - 9}{20}$

Answer 2

Given

• Product of two rational numbers = $\dfrac{-9}{20}$
• One rational number = $\dfrac{-2}{-15}\: or\: \dfrac{2}{15}$

To find

• Another rational number.

Solution

• Let the another rational number be x.

$\tt:\implies\: \: \: \: \: \: \: \: {\dfrac{2}{15} × x = \dfrac{-9}{20}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {\dfrac{2x}{15} = \dfrac{-9}{20}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {20 × 2x = 15 × (-9)}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {40x = -135}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {x = \dfrac{-135}{40}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {x = \dfrac{-27}{8}}$

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