Question

product of zeroes of polynomial p[x]=x^2+3x+2
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Answer 1

Answer:

2

Step-by-step explanation:

p(x) = x² + 3x + 2

to find its zeros

p(x) = 0

x² + 3x + 2 = 0

x² + 2x + x + 2 = 0

x(x + 2) + 1(x + 2) = 0

(x + 2)(x + 1) = 0

thus

case I

x + 2 = 0

x = -2

case ii

x + 1 = 0

x = -1

now product of its zeros

(-2) × (-1) = 2 ans