Product of zeroes of(x2 —3)
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Answer:
-3
Concept used:
In p(x) = ax² + bx + c = 0. the product of zeroes is c/a.
Step-by-step explanation:
p(x) = x² - 3 = 0
a = 1, b = 0, c = -3.
Product of zeroes = c/a = -3 / 1 = -3.
Thus the product of zeroes is -3.
Let's check!
Finding zeroes,
⇒ x² - 3 = 0
⇒ x² = 3
⇒ x = ±√3
Thus the zeroes are √3 and -√3.
Product of zeroes = √3 × -√3 = -3.
Thus it's right!
Diven15:
Thanks alot buddy, it helped
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