Question

proff that 1=2
let a=b ,
a^2= ab ,
a^2-b^2=ab-b^2 ,
(a-b)(a+b)= b(a-b)
a+b=b
b+b=b (a=b above)
2b = b
2=1
can anybody prove it wrong
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Answer 1

Answer:

"Proof": 2 = 1

-2 = -2

4 - 6 = 1 - 3

4 - 6 + 9/4 = 1 - 3 + 9/4

(2 - 3/2)2 = (1 - 3/2)2

2 - 3/2 = 1 - 3/2

2 = 1

Step-by-step explanation:

"Proof" that 1 + 1 = 1

a = 1

b = 1

a = b

a2 = b2

a2 - b2 = 0

(a-b)(a+b) = 0

(a-b)(a+b)/(a-b) = 0/(a-b)

1(a+b) = 0

(a+b) = 0

1 + 1 = 0

2 = 0

1 = 0

1 + 1 = 1

hope its help full

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