Math, asked by singhsunil759, 11 months ago

Profit after selling an article for Rs. 717 is

11 1/9 %


more than the loss incurred when it is

sold at Rs. 527. What would be the selling price

if he want to earn a profit of 10%.

Answers

Answered by ColinJacobus
24

Answer:  The required selling price is Rs. 678.7.

Step-by-step explanation:  Given that the profit after selling an article  for Rs. 717 is  11\dfrac{1}{9}\%  more than the loss incurred when it is  sold at Rs. 527.

We are to find the selling price if he wants to earn a profit of 10%.

Let Rs x be the actual cost price of the article.

We have

\textup{Profit after selling an article for Rs. 717}=Rs. (717-x)

and

\textup{loss after selling the article at Rs. 527}=Rs.(x-527).

According to the given information, we have

(x-527)+\dfrac{100}{9}\%\times(x-527)=717-x\\\\\\\Rightarrow (x-527)+\dfrac{100}{9\times100}(x-527)=717-x\\\\\\\Rightarrow (x-527)+\dfrac{x-527}{9}=717-x\\\\\\\Rightarrow \dfrac{10(x-527)}{9}=717-x\\\\\\\Rightarrow 10x-5270=6453-9x\\\\\Rightarrow 10x+9x=6453+5270\\\\\Rightarrow 19x=11723\\\\\Rightarrow x=617.

So, the cost price of the article is Rs. 617.

Therefore, the selling price of the article to earn a profit of 10% is given by

S=617+10\%\times617=617+61.7=678.7

Thus, the required selling price is Rs. 678.7.

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