Computer Science, asked by shubhn243, 7 months ago

Program for pattern?

#
* #
#*#
*#*#
#*#*#

Answers

Answered by shrdhrgautam
0

Answer:

#*#*# ,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Answered by akinchannayeklovesc
1

Answer:

ans is given below

Explanation:

#include<stdio.h>

void main()

{

 int row=0,col=0,rnum=0;

 printf("enter number of rows:");

 printf("\n");

 scanf("%d",&rnum);

 for(row=1;row<=rnum;row++)

 {

  for(col=1;col<=row;col++)

  {

   if(row%2!=0) //part for odd no. of rows

   {

    if(col%2!=0) //print for odd no. of col

    {

     printf("#");

     }

      else //print for even no. of col

     {

      printf("*");

      }

    }

    else //part for even no. of rows

   {

    if(col%2!=0) //print for odd no. of col

    {

     printf("*");

     }

      else //print for even no. of col

     {

      printf("#");

      }

    }

   }

   printf("\n");

  }

 }

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