Program in c to find an armstrong number between two intervals
Answers
here is your Answer:
#include <stdio.h>
#include <math.h>
int main()
{
int low, high, i, temp1, temp2, remainder, n = 0, result = 0;
printf("Enter two numbers(intervals): ");
scanf("%d %d", &low, &high);
printf("Armstrong numbers between %d an %d are: ", low, high);
for(i = low + 1; i < high; ++i)
{
temp2 = i;
temp1 = i;
// number of digits calculation
while (temp1 != 0)
{
temp1 /= 10;
++n;
}
// result contains sum of nth power of its digits
while (temp2 != 0)
{
remainder = temp2 % 10;
result += pow(remainder, n);
temp2 /= 10;
}
// checks if number i is equal to the sum of nth power of its digits
if (result == i) {
printf("%d ", i);
}
// resetting the values to check Armstrong number for next iteration
n = 0;
result = 0;
}
return 0;
}