Question

Program to calculate the sums of even and odd integers of the first n natural numbers.​

Answer 1

$\huge{\overline{\underline{\bf{\mid{Python}\mid}}}}$

$\huge{\underline{\tt{Codings:-}}}$

n= int(input("Up to which Natural number?"))

ctr=1

sum_even= sum_odd=0

while ctr<=n:

if ctr%2==0:

sum_even+=ctr

else:

sum_odd+=ctr

ctr+=1

print("The sum of even integers is",sum_even)

print("The sum of odd integers is ",sum_odd)

Answer 2

Answer:

Program to Calculate Sum of Even and Odd Numbers from 1 to N without If Statement. This Python sum of even and odd numbers program is the same as the above. However, this program allows users to enter Minimum and maximum value. Next, it prints even and odd numbers between Minimum and maximum value.

If n is even, you are calculating the sum of the first n/2 odd and n/2 even numbers. If n is odd, you are calculating the sum of the first (n+1)/2 odd and the first (n-1)/2 even numbers. Let o=floor((n+1)/2).