Question

PROGRESSIONS QUESTION :-

How many numbers of 2 digits are divisible by 7 ?​

Answer 1

SOLUTION:-

The two digit numbers which are divisible by 7 are 14 , 21 , 28 ,...............98 are in A.P

$t_{n} = 98$

$a + (n - 1)d = 98$

$14 + (n - 1)7 = 98$

$(n - 1)7 = 98 - 14$

$(n - 1)7 = 84$

$(n - 1) = \frac{84}{7}$

$n - 1 = 12$

$n = 13$

Therefore. , 13 numbers of two digits are divisible by 7.