Question

Project 2 cos squared theta minus 1 by sin theta cos theta is equal to 1 minus 2 sin square theta by sin theta cos theta

Answer 1

Answer:

your answer attached in the photo

Answer 2

Solution →

$\frac{2 {cos}^{2}\theta - 1 }{sin \: \theta \times cos \: \theta} = \frac{1 - 2 {sin}^{2}\theta }{sin \:\theta \times cos \: \theta } \:$

LHS →

$= \frac{2 {cos}^{2}\theta - 1 }{sin \: \theta \times cos \: \theta}$

We know that

• ${cos}^{2} \theta \: = 1 - {sin}^{2}\theta \:$

So,

$= \frac{2(1 - {sin}^{2} \theta) - 1}{sin \: \theta \times cos \:\theta }$

$= \frac{2 - 2 {sin}^{2}\theta - 1 }{sin \: \theta \times cos \:\theta }$

$\boxed{\red{= \frac{1 - 2 {sin}^{2}\theta }{sin \: \theta \times cos \: \theta} }}$

RHS

Hence Proved !!

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