Question

project on cyclone tuakte​

Answer 1

Explanation:

Given :-

The circular head of the screw gauge is divided into 20 divisions and the screw moves 1 mm ahead in two rotations of the head of the screw.

To Find :-

Least count

Solution :-

Screw is moving 1mm in two rotation

So, in a rotation it will move = 1/2 = 0.5 mm

Now

Least count = Distance covered in 1 rotation/Total division in it

Least count = 0.5/20

Least count = 05/20 × 1/10

Least count = 05/200

Least count = 0.025 mm