projectile fired at an angle equally inclined to the horizontal and vertical velocity u the horizantal range is
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as the velocity is equally inclined to the horizontal and the vertical then the angle of projection comes out to be 45° .And the range corresponding to this angle is maximum. hence,
Range=(u^2)/g.
Range=(u^2)/g.
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The horizontal range is equal to .
Explanation:
The formula of the horizontal range is given by the formula as :
If the projectile fired at an angle equally inclined to the horizontal and vertical, then
Then,
So, the horizontal range is equal to . Hence, this is the required solution.
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