Question

Projectile is fired from ground level with velocity of 500 m/s at an angle 30 with horizontal find the least velocity with which it cld cover the same horizontal rangle1

Answer 1

Explanation:

An angle of 30° with the vertical is 60° from the ground (horizontal).

The range R of a projectile launched at an angle θ with a velocity Vo is:

R = Vo^2 Sin2θ / g

The maximum height H is

H = Vo^2 Sin^2(θ) / 2g

In this case, Vo = 200m/s, θ = 60° so

H = (200^2)(0.866^2)/19.62

H = (40000)(0.75)/19.62

H = 1529.1

The maximum height is 1529.1m