Question

Projective is projected at an angle of 15 to the horizontal with same velocity V is another projectile is projected with the same speed then at what angle must it be projected with horizontal so as the same horizontal range

Answer 1

As in the case of projectiles, we know that the formula for maximum height is:

h=(u^2)sin(2theta) / g , where theta is the angle with which the projectile was projected with the horizontal.

This formula states that the maximum height reached by the projectile is directly proportional to the sine of double angle.

So, the ratio will be sin(60)/sin(120)= 1

Also, as these angles are complementary, i.e. 60+30 = 90 degrees

The maximum height reached by these projectiles will be same.