Math, asked by prashantthegamp7xv8z, 1 year ago

proof 2m, m^2-1, m^2+1 is a pythagorean triplet

Answers

Answered by BlackVenom05
32
hey friend,
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Lets take 8 as example....

Let 2m= 8
m= 8/2 = 4

Therefore,
2m = 2(4) = 8
m²-1 = 4²-1 = 15
m²+1 = 4²+1= 17

Pythagorean Triplet = 8,15,17
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i hope this answer helps you...

BlackVenom05: thnz for marking brainliest
Answered by shraddha9831
14

Step-by-step explanation:

for example, let's take 6 as 2m

2m =6

m^2 + 1 = 6/2^2 +1 = 10 (on solving)

m^2 - 1 = 6/2^2 - 1 = 8 (on solving)

hence,the Pythagorean triplet is 2,8,10.

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