Question

proof
3x(x+y+z)-2y(x-y+z) from 4z(-x+y+z) = -3x²-2y²+4z²-xy+6yz-7xz

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Answer 1

Answer:

To Subtract:-

3x(x+y+z)-2y(x-y+z) from 4z(-x+y+z)

Solution:-

Given R.H.S= -3x²-2y²+4z²-xy+6yz-7xz

We've to prove L.H.S, the same

Let's prove it

[4z(-x+y+z)]-[3x(x+y+z)-2y(x-y+z)]

(-4xz+4yz+4z²)-(3x²+3xy+3xz-2xy+2y²-2yz)

-4xz+4yz+4z²-3x²-3xy-3xz+2xy-2y²+2yz

Arrange in order of like terms

-4xz-3xz+4yz+2yz+4z²-3x²-3xy+2xy-2y²

-7xz+6yz+4z²-3x²-xy-2y²

Arrange in the alphabetical order

-3x²-2y²+4z²-xy+6yz-7xz

L.H.S= -3x²-2y²+4z²-xy+6yz-7xz

R.H.S= -3x²-2y²+4z²-xy+6yz-7xz

L.H.S=R.H.S

Hence verified

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