proof (a+b)^2=a^2+b^2+2ab
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2
(a+b) * (a+b) = a2 +ab + ba + b2 = a2 + 2ab + b2
hence a²+b²+2ab
hence a²+b²+2ab
Answered by
6
(a+b)(a+b)=
a×a +a×b +b×b +a×b=
a^2+b^2+ab + ab=
a^2+b^2+2ab
a×a +a×b +b×b +a×b=
a^2+b^2+ab + ab=
a^2+b^2+2ab
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