proof (a+b)square - (a-b)square = 4ab
muskan1143:
can u prove it
by lhs or RHS?
by any side
break the bracket of rhs
ok thanks
(a+b+c) (a^2 +b^2 +c^2 - ab-bc-ac) = a(a^2 +b^2 +c^2 - ab-bc-ac) + b(a^2 +b^2 +c^2 - ab-bc-ac) +c(a^2 +b^2 +c^2 - ab-bc-ac)
ur welcome
calculate it all
if uh want to prove it by lhs then do it by factorization
ok
Answers
Answered by
20
Heya!!
= (a+b) ^2 - (a-b) ^2
= (a^2 + b^2 + 2ab) - (a^2 + b^2 - 2ab)
= 2ab + 2ab
= 4ab
Hope it helps uh!
= (a+b) ^2 - (a-b) ^2
= (a^2 + b^2 + 2ab) - (a^2 + b^2 - 2ab)
= 2ab + 2ab
= 4ab
Hope it helps uh!
Answered by
8
(a+b)^2=a^2+2ab+b^2
(a-b)^2 = a^2-2ab+b^2
(a+b)^2-(a-b)^2=( a^2+2ab+b^2)-(a^2-2ab+b^2)
= a^2+2ab+b^2-a^2+2ab-b^2
=2ab+2ab
=4ab
(a-b)^2 = a^2-2ab+b^2
(a+b)^2-(a-b)^2=( a^2+2ab+b^2)-(a^2-2ab+b^2)
= a^2+2ab+b^2-a^2+2ab-b^2
=2ab+2ab
=4ab
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