Question

proof , A diogonal of a parallelogram bisects into two congruent triangles​

Answer 1

Answer:

Given: A parallelogram ABCD and AC is its diagonal .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have  

∠DAC =  ∠BCA [alt. int. angles, since AD | | BC]  

AC = AC [common side]  

and ∠BAC =  ∠DAC [alt. int. angles, since AB | | DC]  

∴ By ASA congruence axiom, we have  

△ABC ≅ △CDA