Question

proof a square + b square
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Answer 1

Answer:

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Step-by-step explanation:

Given that, we have to prove:

a^2-b^2 = (a+b)(a-b)

Take the RHS of above identity,

(a+b)(a-b)

Multiply each term in first bracket with each term in second bracket

(a+b)(a-b) = a^2 -ab + ab -b^2

-ab and ab cancels each other

Therefore, we get,

(a+b)(a-b) = a^2-b^2

LHS = RHS

Thus the formula is proved

Answer 2

Answer:

(a+b)2−2ab

=(a+b)(a+b)−2ab

=a2+ab+ab+b2−2ab

=a2+2ab+b2−2ab

=a2+b2

Proved!

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