Proof a³+b³+c³=3abc ,if a+b+c=0
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lhs=a^3+b^3+c^3
a^3+b^3+c^3-3abc+3abc
(a+b+c)(a^2+b^2+c^2-ac-bc-ab)+3abc
LHS=3abc=RHS. (:a+b+c=0)
a^3+b^3+c^3-3abc+3abc
(a+b+c)(a^2+b^2+c^2-ac-bc-ab)+3abc
LHS=3abc=RHS. (:a+b+c=0)
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