Math, asked by prajjvalh606, 1 year ago

Proof a³+b³+c³=3abc ,if a+b+c=0

Answers

Answered by aman9340
6
lhs=a^3+b^3+c^3

a^3+b^3+c^3-3abc+3abc

(a+b+c)(a^2+b^2+c^2-ac-bc-ab)+3abc

LHS=3abc=RHS. (:a+b+c=0)
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