Question

Proof for the sum of: I) interior and II) exterior angles of a nonagon..
keep in mind its proof ..pls tell ...i will mark u as brain list for correct and complete answer.

Answer 1

Answer:

The sum of the exterior angles of any polygon is 360.

For a regular nonagon each exterior angle = 360/9 = 40 deg.

Each interior angle is 180–40 = 140 deg.

Another approach: Sum of the interior angles of a nonagon = (n-2)* 180 = 7*180 = 1260 deg.

Answer 2

Step-by-step explanation:

sum of the exterior angles of a polygon = 360

for a regular nonagon, each exterior angle is

360/9=40 degrees and

each interior angle = 360-exterior angle

= 360-40

= 140 degrees