Question

proof for trignometry​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$(sinA-cosA+1)/(sinA+cosA-1)\\\=(sinA/cosA-cosA/cosA+1/cosA)/(sinA/cosA+cosA/cosA-1/cosA)\\\\=(tanA-1+secA)/(tanA+1-secA)\\\\=(tanA+secA-(sec^{2}A-tan^{2}A))/(tanA-secA+1) \\\\=((tanA+secA)-(secA-tanA)(secA+tanA))/((tanA-secA)+1)\\\\=((tanA+secA)(1-secA+tanA)/((1-secA+tanA)\\tanA+secA$