Proof in a rectangle ABCD AO is equal to CO and BO is equal to DO
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Answered by
1
Do via angles..
Angle AOB=AOC.. vertically..
angle ABO=ODC...alternate..
angleBAO=OCD....alternate
So these 2 triangles are congruent
By cpct AO=OF
similarly BO=DO
hence proves
Angle AOB=AOC.. vertically..
angle ABO=ODC...alternate..
angleBAO=OCD....alternate
So these 2 triangles are congruent
By cpct AO=OF
similarly BO=DO
hence proves
Anonymous:
hey, AAA is not any criteria for congruency
yea..
Moreover diagonals bisect each other..
dont get confused between congruency and similarity......here the triangles will be proved congruent by SAS as opposite sides of a rectangle are equal
we have to prove that diagonals bisect each other here
edit ur ans before somebody reports it
Answered by
1
Hope it helps..
Cheers :D !
Cheers :D !
Attachments:
i guess he was asking for proof
Ooops..
edit ur ans
done
:sweat_smile:
hehehe.....whats this now
*Correction*
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