Question

Proof law of conservation of linear momentum

Answer 1

mu1+mu2=mv1+mv2 the is formula of linear momentum

Answer 2

hey dude.....
ur answer is here.....!!!!!

Let
consider two bodies of masses m1 and m2 moving in straight line in the same direction with initial velocities u1 and u2. They collide for a short time ∆t.
After collision,
they move with velocities v1 and v2.From 2nd law of motion,

Force applied by A on B = Rate of change of momentum of B FAB
= (m2v2-m2u2)/∆tSimilarly,

Force applied by B on A = Rate of change of momentum of AFBA
= (m1v1-m1u1)/∆t

From Newton’s 3rd law of motion,
FAB = -FBAOr,
(m2v2-m2u2)/∆t = -(m1v1-m1u1)/∆tOr, m2v2-m2u2 = -m1v1+m1u1Or, m1u1 + m2u2 = m1v1 + m2v2
This means the total momentum before collision is equal to total momentum after collision.
This proves the principle of co conservation of linear momentum.

thanks.....!