proof of √3 is irrational
4th step answer it ( class 10th )
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Let us assume that√3 is rational
√3 = p/q, q not equal to 0
squaring on both sides
(√3)^2 = (p/q)^2
3 = p^2/q^2
by cross multiplication
3q^2 = p^2...........1
p^2 is multiple of 3
p is multiple of 3
3q^2 = (3k)^2
3q^2 = 3^2k^2
q^2 = 3k^2......2
q^2 is multiple of 3
q is multiple of 3
therefore (p,q) = 3
our assume is wrong
so, √3 is irrational.
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