proof of area of parallelogram equal (b x h)
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The formula is A = b x h and it is really simple to prove. If we cut a triangle off of one end of a parallelogram and move it to the other end, we get a RECTANGLE, whose area is the same as the based of the parallelogram times its height.
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Let ABCDABCD be the parallelogram whose area is being sought.
Let FF be the foot of the altitude from CC
Also label a point EE such that DEDE is the altitudefrom DD (see figure above).
Extend ABAB to FF.
Then:
ADAD≅≅BCBC∠AED∠AED≅≅∠BFC∠BFCDEDE≅≅CFCF
Thus:
△AED≅△BFC⟹(AED)=(BFC)△AED≅△BFC⟹(AED)=(BFC)
So:
(ABCD)=EF⋅FC=AB⋅CF(ABCD)=EF⋅FC=AB⋅CF
■◼
Glad to help u
Let FF be the foot of the altitude from CC
Also label a point EE such that DEDE is the altitudefrom DD (see figure above).
Extend ABAB to FF.
Then:
ADAD≅≅BCBC∠AED∠AED≅≅∠BFC∠BFCDEDE≅≅CFCF
Thus:
△AED≅△BFC⟹(AED)=(BFC)△AED≅△BFC⟹(AED)=(BFC)
So:
(ABCD)=EF⋅FC=AB⋅CF(ABCD)=EF⋅FC=AB⋅CF
■◼
Glad to help u
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