Question

proof of Keplers 3rd law​

Answer 1

Answer:

Hope it may helps uu......

Answer 2

The Kepler's third law of planetary motion:-

the cube of the mean distance of a planet from the sun is directly proportional to the square of time it takes to move around the sun......

${r}^{3}directly \: propotion \: to \: { t}^{2}$

${r}^{3} = constant \times {t}^{2}$

$\frac{ {r}^{3} }{ {t}^{2} } = contant$

r= mean distance s of the planet from the sun

T=time period of the planet (around the sun)