Question

Proof of locus of projectile

Answer 1

Since we have(x−0)2+{y−(−1)}2=|y−1|2,(x−0)2+{y−(−1)}2=|y−1|2,we havex2=4⋅(−1)⋅y.x2=4⋅(−1)⋅y.The vertex is (0,0)(0,0), the axis of symmetry is x=0x=0, the focus is (0,−1)(0,−1), the directrix is y=−(−1)y=−(−1).