proof pythagorus theorum
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in a right angle the square of the length of the hypotenuse is equal to the sum of the square of the length of legs there are several methods to prove the Pythagorean theorem......
given triangle ABC prove that a2 +b2=c2 .
first construct a perpendicular from C to AB
given triangle ABC prove that a2 +b2=c2 .
first construct a perpendicular from C to AB
gwadhwa2003:
Give the complete proof as well as the figure
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lPythagoras Theorem Proof
Given: A right-angled triangle ABC.
To Prove- AC² = AB² + BC²
Proof: First, we have to drop a perpendicular BD onto the side AC
We know, △ADB ~ △ABC
Therefore,
AD AB
----- = -----
AB AC
(Condition for similarity)
Or, AB² = AD × AC …………………..……..(1)
Also, △BDC ~△ABC
Therefore,
CD BC
----- = -----
BC AC
(Condition for similarity)
Or, BC²= CD × AC …………………………..(2)
Adding the equations (1) and (2) we get,
AB² + BC² = AD × AC + CD × AC
AB² + BC² = AC (AD + CD)
Since, AD + CD = AC
Therefore, AC² = AB² + BC²
Hence, the Pythagorean thoerem is proved.
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