proof rhis statement Given positive integers A and B, there exist whole numbers Q and R satisfying A = BQ + R , 0 ≤
R <
b
Answers
Answered by
0
Answer:
a=bq+r
if 3 divides 13 quotient =4 and remainder=1 divisior(b) = 3 dividend(a) = 13
Step-by-step explanation:
a=13 b=3 q=4 r=1
a= bq+ r
13 = 3×4+1
13= 12+1
13=13
therefore a=bq+r
hope this helps and pls follow me
Similar questions