Math, asked by kuthoogowhar444, 9 months ago

proof rhis statement Given positive integers A and B, there exist whole numbers Q and R satisfying A = BQ + R , 0 ≤

R <

b

Answers

Answered by vidyavandana39
0

Answer:

a=bq+r

if 3 divides 13 quotient =4 and remainder=1 divisior(b) = 3 dividend(a) = 13

Step-by-step explanation:

a=13 b=3 q=4 r=1

a= bq+ r

13 = 3×4+1

13= 12+1

13=13

therefore a=bq+r

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