proof sin square theta + cos sqaure theta =1
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Heya☺
In right triangle
sina = P/H
cos a = B/H
By Pythagoras theorem
H^2 = P^2 + B^2
Dividing each term by H^2
H^2/H^2 =. B^2/H^2 + P^2/H^2
1 = sin^2a + cos ^2 a
✌
In right triangle
sina = P/H
cos a = B/H
By Pythagoras theorem
H^2 = P^2 + B^2
Dividing each term by H^2
H^2/H^2 =. B^2/H^2 + P^2/H^2
1 = sin^2a + cos ^2 a
✌
ompream:
kya bat sanaya ji
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