Proof that
0! = 1!
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n! is defined as the product of all positive integers from 1 to n, then:
1! = 1×1 = 1
2! = 1×2 = 2
3! = 1×2×3 = 6
4! = 1×2×3×4 = 24
n! = 1×2×3×(n-2)×(n-1)*n
and so on.
Logically, n! can also be expressed n*(n-1)! .
Therefore, at n=1, using n! = n*(n-1)!
1! = 1*0!
which simplifies to 1 = 0!
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