Question

proof that √{(1-sin²θ)/(1+sin²θ)}=secθ-tanθ

Answer 1

Step-by-step explanation:

√(1-sin^2 theta) / (1+sin^2 theta)

rationalise the denominator

√ (1-sin^2theta ) ^2/1 - sin^4 theta

√ cos ^4 theta / 1 - cos ^4 theta / sin^4 theta

sec theta - tan theta