Question

proof that 100-100/100-100=2​

Answer 1

Answer:

It can be proved but this is not a correct mathematical problem as in maths denominator can never be 0.

PROOF

100-100/100-100 = $\frac{10^{2} - 10^{2} }{10(10 - 10 )}} = \frac{(10-10)(10+10)}{10(10-10)} = \frac{10 + 10}{10} = \frac{20}{10} = 2$

Answer 2

$\mathfrak{dear\;user }$

$\mathfrak{question-}$prove 100-100/100-100=2 ​

$\mathfrak{here\:is\:the\:solution\:for \:the question }$

$a^{2}-b^{2} =(a+b)(a-b)$

$= (100-100)\div (100-100)=2$

$L.H.S$

=$(10^{2} -10^{2})\div10(10-10)$

=$(10+10)(10-10)\div10(10-10)$ $cancel$$(10-10)$$from \:numerator \:and \:denominatior.$

=$10+10\div10$

=$20 \div 10$

$=2$

$R.H.S=2$

$\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS }10\:thanks\:and \:brainlist$

$\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}$

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