proof that √3,√5,√7,√3+2,√3+5 irrational number
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Answered by
2
Answer:
Assume that 3+25 is rational. Then,
3+25=ba
5=2ba−3b
This gives that 2ba−3b is rational but 5 is an irrational number, therefore, the assumption is wrong.
Hence, 3+25 is irrational.
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Answered by
1
Step-by-step explanation:
Assume that 3+2 5 is rational. Then,
3+2
5 = b
aa =
2b
a−3b
This gives that
2b
a−3b
is rational but
5
is an irrational number, therefore, the assumption is wrong.
Hence, 3+2
5
is irrational.
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