Question

proof that angle between the internal bisector of two angles of a triangle is sum of half of the third angle and right angle

Answer 1

Step-by-step explanation:

I will first ask you to draw a right-angled triangle.Mark the angles other than 90 as 2x and 2y.Now when you draw the bisectors of 2x and 2y,then half of the angles becomes x and y,and the angle formed by the bisectors is 180-(x+y).Now in the original triangle the third angle is 180-(2x+2y).and it's half is 90-(x+y).when you add right angle to it i.e. ,90-(x+y)+90 gives you 180-(x+y).Hence proved.