Question

Proof that angle opposite to equal sides of an isosceles triangle are equal

Answer 1

Answer:in ΔABC let AD be the angle bisector of angle A.

InΔabd and Δadc,

AB=AC(given)

AD=AD(common)

<BAD =<DAC

So by SAS congruency rule both triangles are congruent.

Therefore, <B=<C (C. P. C. T)

Hence proved.