proof that bc ( b+c) + ca ( c+a) + ab ( a+b) + 2abc = (a+b) (b+c) (c+a)
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Step-by-step explanation:
bc(b+c)+ca(c+a)+ab(a+b)++2ab
(b+c)(c+a) (b+a)
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Step-by-step explanation:
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