proof that cosa/1-sina + cosa/1+sina = 2seca
Answers
Answered by
1
Answer:
Step-by-step explanation:
LHS
[cosA/(1-sinA)] + [cosA/(1+sinA)
Taking LCM
[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]
=(cosA+cotA + cosA - cotA)/(1-sin²A)
=2cosA/cos²A
=2/cosA
=2secA
RHS
Answered by
1
Step-by-step explanation:
LHS
[cosA/(1-sinA)] + [cosA/(1+sinA)
Taking LCM
[cosA(1+sinA) + cosA(1-sinA)]/[(1-sinA)(1+sinA)]
=(cosA+cotA + cosA - cotA)/(1-sin²A)
=2cosA/cos²A
=2/cosA
=2secA
RHS
Similar questions