Math, asked by rajamrit9704, 4 months ago

proof that cosA + sinA +1÷cosA +sinA-1 = cosecA + cotA

Answers

Answered by bhumikakhandelwalvis

1

Step-by-step explanation:

LHS=

cosA+sinA−1

cosA−sinA+1

dividing Nr and Dr by sinA we get,

=

sinA

cosA

+

sinA

sinA

−

sinA

1

sinA

cosA

−

sinA

sinA

+

sinA

1

=

cotA+1−cosecA

cotA−1+cosecA

=

cotA+1−cosecA

cotA+cosecA−(cosec

2

A−cot

2

A)

=

cotA+1−cosecA

(cotA+cosecA)(1−cosecA+cotA)

=cotA+cosecA=RHS

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