Question

proof that if chord of congruent circle subtend equal at their centres​

Answer 1

Answer :

In △AOB and △PXQ,

AO=PX [Radius of congruent circles are equal]

∠AOB=∠PXQ (Given)

BO=QX [Radius of congruent circles are equal]

△AOB≅△PXQ [SAS congruence rule]

∴AB=PQ [CPCT]

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Answer 2

Answer:

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