proof that. n(aub)=n(a)+n(b)-n(a∩b)
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Answer:
n(aub) includes n(a)+n(b)-n(a( b)
Step-by-step explanation:
let us take a to multiples of 3 and b to be multiples of 4
total possibility is 20
10= 6+5-1
10=10
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