Question

proof that (p-q)²+4pq=(p+q)²​

Answer 1

Opening the whole term of RHS as well as LHS,

We have,

[p²+q²-2pq]+4pq=p²+q²+2pq

solving RHS,

p²+q²+2pq=p²+q²+2pq

Since, LHS=RHS,

(p-q)²+4pq=(p+q)²​

Hence Proved!