proof that, s= ut + 1/2 (at^2)
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Answered by
4
we know v = u + a t
ds/dt = u + a t
we integrate wrt t on both sides
s = u t + 1/2 a t²
============================
another way:
v - u = a t
avg speed = (iniitial + final speed)/2
distance travelled: s = avg speed * time duration
s = (v+u)/2 * t
s =(u + at + u) t /2
s = u t + 1/2 a t²
ds/dt = u + a t
we integrate wrt t on both sides
s = u t + 1/2 a t²
============================
another way:
v - u = a t
avg speed = (iniitial + final speed)/2
distance travelled: s = avg speed * time duration
s = (v+u)/2 * t
s =(u + at + u) t /2
s = u t + 1/2 a t²
Answered by
0
Answer:
correct bro ...........................
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