Question

Proof that the sum of the first n odd positive integers is n2

Answer 1

Answer:

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Step-by-step explanation:

let the series of first n odd possitive no is 1,3,5..........

a=1 d=2 then

sn=n/2(2a+(n-1)d)

=n/2(2×1+(n-1)2)

=n/2(2+2n-2)

=n/2(2n)

=n^2