Question

proof that time of ascent(Ta) =time of descent(Td) ​

Answer 1

Answer:

Step-by-step explanation:

ta=td

replacement of the values

u/g=u/g

ta=u/g

td=u/g

hence ta=td

Answer 2

Answer:

When the object is thrown vertically upward

then u=0

time=t1

by applying

v=u+gt1

here acceleration due to gravity (g)= -ve

object is moving against the gravity

0=u-gt1

u=gt1

t1=u/g...........(1)

when the object is coming downward

then u=0, time=t2

by applying

v=u+gt2

v=0+gt2

the object falls back to the earth with the same velocity as it was thrown vertically upward

v=u

hence u=gt2

u/g=t2.........(2)

from equation 1 and 2

t1=t2 PROVED

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